PHP date_sub() Function
Example
Subtract 40 days from the 15th of March, 2013:
<?php
$date=date_create("2013-03-15");
date_sub($date,date_interval_create_from_date_string("40 days"));
echo date_format($date,"Y-m-d");
?>
Run example »
Definition and Usage
The date_sub() function subtracts some days, months, years, hours, minutes, and seconds from a date.
Syntax
date_sub(object,interval);
| Parameter | Description |
|---|---|
| object | Required. Specifies a DateTime object returned by date_create() |
| interval | Required. Specifies a DateInterval object |
Technical Details
| Return Value: | Returns a DateTime object on success. FALSE on failure |
|---|---|
| PHP Version: | 5.3+ |
❮ PHP Date/Time Reference
