MySQL SUBDATE() Function
Example
Subtract 10 days from a date and return the date:
SELECT SUBDATE("2017-06-15", INTERVAL 10 DAY);
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Definition and Usage
The SUBDATE() function returns a date after a certain time/date interval has been subtracted.
Syntax
SUBDATE(date, INTERVAL value unit)OR:
SUBDATE(date, days)Parameter Values
| Parameter | Description |
|---|---|
| date | Required. The date to be modified |
| days | Required. The number of days to subtract from date |
| value | Required. The value of the time/date interval to subtract. You can specify positive and negative values for this parameter |
| unit | Required. The unit type of the interval. Can be one of the following
values:
|
Technical Details
| Works in: | MySQL 5.7, MySQL 5.6, MySQL 5.5, MySQL 5.1, MySQL 5.0, MySQL 4.1, MySQL 4.0, MySQL 3.23 |
|---|
More Examples
Example
Subtract 15 minutes from a date and return the date:
SELECT SUBDATE("2017-06-15 09:34:21", INTERVAL 15 MINUTE);
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Example
Subtract 3 hours from a date and return the date:
SELECT SUBDATE("2017-06-15 09:34:21", INTERVAL 3 HOUR);
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Example
Add 2 months to a date and return the date:
SELECT SUBDATE("2017-06-15", INTERVAL -2 MONTH);
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