THE WORLD'S LARGEST WEB DEVELOPER SITE
HTML CSS JAVASCRIPT SQL PHP BOOTSTRAP HOW TO JQUERY W3.CSS ANGULARJS XML MORE FORUM EXAMPLES REFERENCES

SQL Server DATEPART() Function

❮ SQL Server Functions

Example

Return a specified part of a given date, as an integer value:

SELECT DATEPART(year, '2017/08/25') AS DatePartInt;
Try it Yourself »

Definition and Usage

The DATEPART() function returns a specified part of a given date, as an integer value.

Syntax

DATEPART(interval, date)

Parameter Values

Parameter Description
interval Required. The time/date part to return. Can be one of the following values:
  • year, yyyy, yy = Year
  • quarter, qq, q = Quarter
  • month, mm, m = month
  • dayofyear = Day of the year
  • day, dy, y = Day
  • week, ww, wk = Week
  • weekday, dw, w = Weekday
  • hour, hh = hour
  • minute, mi, n = Minute
  • second, ss, s = Second
  • millisecond, ms = Millisecond
date Required. The date to use

Technical Details

Works in: SQL Server 2014, SQL Server 2012, SQL Server 2008 R2, SQL Server 2008, SQL Server 2005

More Examples

Example

Return a specified part of a given date, as an integer value:

SELECT DATEPART(yy, '2017/08/25') AS DatePartInt;
Try it Yourself »

Example

Return a specified part of a given date, as an integer value:

SELECT DATEPART(month, '2017/08/25') AS DatePartInt;
Try it Yourself »

Example

Return a specified part of a given date, as an integer value:

SELECT DATEPART(hour, '2017/08/25 08:36') AS DatePartInt;
Try it Yourself »

Example

Return a specified part of a given date, as an integer value:

SELECT DATEPART(minute, '2017/08/25 08:36') AS DatePartInt;
Try it Yourself »

❮ SQL Server Functions